SOCI 3311 Blog

That's one way for these 3 values to be identical.

The mean, median, and mode will also be identical if a distribution is perfectly symmetrical.

1-3 is false for the reason you state.

1-4 is true as changing the unit does Not change the correlation coefficient

For example, if you had X's and Y's representing dollars and you converted the X's and Y's to cents, the correlation would remain the same.

The t value given is the calculated value of t or 't obtained.'

The p value is the exact probability of getting 't obtained' (in absolute value .. i.e. no sign) of this size of larger.

In other words, p represents the area to the right of + t obtained and to the left of - t obtained (remember 2 tails).

Hence, if this p value is equal to or less than α, you will ALWAYS reject the null hypothesis.

If this p value is greater than α, you will ALWAYS fail to reject the null hypothesis.

In other words, you can compare 'p' to 'α' to make your decision instead of using a t critical value.

You use the population standard deviation if it is know. If it is NOT know, substitute the sample standard deviation.

However, once you substitute the sample standard deviation, you must use a critical t instead of a critical z.

Thanks so much for the kind words. :)

With replacement:

The p of 1 ace is 4/52 or 1/13

The probability of an ace followed by an ace followed by an ace followed by an ace equals:

1/13 X 1/13 X 1/13 X 1/13

Don't spend too much time on 'basic probability' -- that is Unit 6. If you will note, I did not devote much time to it in the homework.

There are 0 questions on the final on Basic Probability.

omg. I've spend all day on this.

The normal distribution is a PROBABILITY distribution.

Hence, when you read area, you interpret it as a PROBABILITY.

For example, the probability of selecting a term for a normal distribution with a z score equal to or less than -2.00 is?

Simply read the area BELOW or TO THE LEFT OF -2.00. This area IS the probability.

Nothing more needs to be done since we are conceptualizing the normal distribution as a PROBABILITY distribution.

First, you will need to find the z score that creates a boundary placing .3 area ABOVE the boundary and .7 area below the boundary.

I did this using the percentile rank calculator. Enter the % of area below this boundary which is .7 times 100 or 70. That is enter 70. The calculator returns a z score of .52.

Now we are working with the one sample z formula:

Here's our substitution:

.52 = (X - 55)/(40/sqrt(36))

.52 = (X - 55)/(40/6) or (X - 55)/6.67

.52 = (X - 55)/6.67

Now solve for X:

X = 58.5

Will exceed what number? 58.5

Sorry.. Redoing.. For some reason I thought you were talking about 1 die initially.

p of odd = 1/2

p of even = 1/2

p of odd follows by an even is 1/2 X 1/2 or 1/4

On second read.. you are talking about one balanced die.

Answer stands.

p of odd = 3/6 or 1/2

p of even = 3/6 or 1/2

p of odd followed by even = 1/2 X 1/2 or 1/4

I think what's throwing me is the "followed by" leads me to permutation formula.